22x^2-3x-6x^2+3x+49=0

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Solution for 22x^2-3x-6x^2+3x+49=0 equation: 



22x^2-3x-6x^2+3x+49=0

We add all the numbers together, and all the variables

16x^2+49=0

a = 16; b = 0; c = +49;
Δ = b2-4ac
Δ = 02-4·16·49
Δ = -3136
Delta is less than zero, so there is no solution for the equation

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